SSC JE Civil Engineering 30-Oct-2020 Shift 1 Paper

Question : 176 of 200

Marks: +1, -0

For a fixed-end beam of length L and central point load of W, what will be the value of W at collapse?
(Note: Plastic moment capacity of beam =

\M_\p

)

Solution:

Mechanism for the given beam will be

{\W} × {{\L}}/{2} \θ={\M}_{{\p}} × \θ+{\M}_{{\p}} × 2 \θ+{\M}_{{\p}} × \θ

{\W}={8 {\M_\p}}/{{\L}}

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