SSC JE Civil Engineering 25-Sep-2019 Shift 1 Solved Paper

Question : 194 of 200

Marks: +1, -0

An iceberg floats in sea water with 14% of its volume projecting above the sea surface. If the specific weight of sea water is 10400 N/m

^{3}

, determine the specific weight of the iceberg (in N/m

^{3}

units).

Solution:

Weight of Iceberg = Displace water
= 10400 N/m

^{3}

× 0.86 V

_o

Where V

_o

is volume of Iceberg
So, Iceberg density =

[\Weight/\Volume]

[{10400 ×0.86V_ o}/{V_ o}]

= 8944 KN/m

^{3}

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