SSC JE Civil Engineering 25-Sep-2019 Shift 1 Solved Paper

Question : 183 of 200

Marks: +1, -0

The modulus of elasticity of M25 concrete as per the formula is IS 456 : 2000 is:

Solution:

The modulus of elasticity as per IS:456 – 1978

E_c= 5700√ E_\ck \;N \/ mm^2

The modulus of elasticity as per IS: 456:2000

E_c= 5000√ E_\ck \;N \/ mm^2

For M25

E_c= 5700√ E_\ck

= 28,500 Mpa as per IS : 456 – 1978

E_c= 5000√ E_\ck

= 25,000 Mpa as per IS : 456 : 2000

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