SSC JE Civil Engineering 2018 Set 3 Solved Paper

Question : 191 of 200

Marks: +1, -0

A lift of weight W is lifted by a rope with an acceleration f. If the area of cross-section of the rope is A, the stress in the rope is

Solution:

Stress

= \Force/ \Area

Force (F) = m × a
acceleration a = g – (–f)
a = g + f

F=(w/g )(g+\f)

∴ Stress

= F/A={w/g (g+\f)}/A

Stress =

{w (1+\f/g)}/A

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