SSC JE Civil Engineering 2018 Set 3 Solved Paper

Question : 190 of 200

Marks: +1, -0

A rolled steel joist is simply supported at its end and carries a uniformly distributed load which causes a maximum deflection of 10 mm and slope at the ends of 0.002 radian. The length of the joist will be

10 m
12 m
14 m
16 m

Validate

Solution:

Slope

(θ_C\A)={W\l^3}/{24EI}

Deflection

( δ _C)=5/384{W\l^4}/{EI}

0.002={W\l^2}/{24EI}

10× 10^{-3}={{W\l^4}.5}/{I6 ×24EI}

10× 10^{-3}=5/10×0.002×\l

[\l=16\m]

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