SSC GD Constable 4 Feb 2025 Shift 1 Paper

Time $=$ Distance $∕$ Relative Speed
Calculation:
Distance $=$ Length of Train $1+$ Length of Train 2
⇒ Distance $=210\mathit{m}+140\mathit{m}=350\mathit{m}$
Relative Speed $=$ Speed of Train 2 - Speed of Train 1
Relative Speed $=150\mathit{k}\mathit{m}∕\mathit{h}-80\mathit{k}\mathit{m}∕\mathit{h}=70\mathit{k}\mathit{m}∕\mathit{h}=70\times \left(5∕18\right)\mathit{m}∕\mathit{s}$
⇒ Relative Speed $=350∕18\mathit{m}∕\mathit{s}$
Time $=$ Distance $∕$ Relative Speed
⇒ Time $=350\mathit{m}∕\left(350∕18\right)\mathit{m}∕\mathit{s}$
⇒ Time $=18\mathit{s}\mathit{e}\mathit{c}=18∕60$ minutes
⇒ Time $=0.3$ minutes