Find the value of [(48 \div 8) \times \{\frac{49}{7} + \frac{40}{4} \times (7−3)\} ]

SSC GD Constable 4 Feb 2025 Shift 1 Paper

Section: Elementary Mathematics

Question : 54 of 80

Marks: +1, -0

Find the value of

[(48 ÷ 8) × \{\;{49}/{7} + \;{40}/{4} × (7−3)\} ]

Solution:

[(48 ÷ 8) × \{\;{49}/{7}+\;{40}/{4} ×(7-3)\} ]

Calculation:

\;{[(48 ÷ 8) ×\{(49) \/(7)+(40) \/(4) ×(7-3)\}]}

\;⇒[(48 ÷ 8) ×\{(49) \/(7)+(40) \/(4) ×(4)\}]

\;⇒[(48 ÷ 8) ×\{(49) \/(7)+(10) ×(4)\}]

\;⇒[(48 ÷ 8) ×[7+40]

\;⇒[6 × 47]

\;⇒ 282

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