SSC CPO SI and ASI Model Paper 9

(2) According to the given condition,The base of the isosceles triangle= the base of the parallelogram= x cm
The isosceles triangle isconstructed between the parallelsides of the parallelogramTherefore, the vertical distancebetween the parallel sides is thealtitude of that triangle
Hence, the area of the triangle
$=\frac{1}{2}\times$area of parallelogram
Also, area of triangle$=\frac{1}{2}$×base ×height
$\Rightarrow \frac{1}{2}\times \mathit{x}\times 52=832$
$\Rightarrow \mathit{x}=\frac{832}{26}=32$
Therefore, the other parallel side= 32 cm