If x /{{x^2}- 4x+1}=1/ 13 , find the value of 1+1/x.

SSC CPO SI and ASI Model Paper 7

Question : 147 of 200

Marks: +1, -0

x /{{x^2}- 4x+1}=1/ 13

, find the value of

1+1/x.

Solution:

(2)

x/{x^2-4x+1}=1/13

⇒13x=x^2-4x+1

⇒x^2-17x+1=0

⇒x[x+1/x]=17x

⇒[x+1/x]=17

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