For what value of \theta, \sec^2 \theta + \tan^2\theta = 3 ? (where 0^\circ \leq \theta \leq 90^\circ)

SSC CPO SI and ASI Model Paper 6

Question : 133 of 200

Marks: +1, -0

For what value of

θ, sec^2 θ + tan^2θ = 3 ? (where 0° ≤ θ ≤ 90°)

Solution:

(3)

sec^2θ+ tan^2θ = 3

⇒1 + tan^2θ+ tan^2θ= 3

⇒2 tan^2θ= 2

⇒tan^2θ= 1

⇒ θ= 45°

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