If 2X+1/3X= 4, then what is the value of 27x^3+1/ {8x^3} ?

SSC CPO SI and ASI Model Paper 3

Question : 110 of 200

Marks: +1, -0

2X+1/3X= 4

, then what is the value of

27x^3+1/ {8x^3} ?

Solution:

2x+1/3x= 4

Multiply both sides by 3/2,

3x+1/{2x} =6

27x^3+1/8x^3

By cubing both sides:

+3(3x)[1/{2x}][3x+1/2x]=216

27x ^3+1/8x^3 =216-27= 189

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