Angle of elevation from the top of a building of height 50 m to the top of a mountain is 30°. If building is45 \sqrt3m away from the mountain, then what is the height of the mountain?

SSC CPO SI and ASI Model Paper 3

Question : 106 of 200

Marks: +1, -0

Angle of elevation from the top of a building of height 50 m to the top of a mountain is 30°. If building is

45 √3

m away from the mountain, then what is the height of the mountain?

Solution:

(4) Let the height of the mountainbe AC.

tan

30°={AB}/{45√ 3}

⇒1/√3={AB}/{45√3 }

⇒AB 45m
.Height of the mountain is AC = AB +BC = 45 + 50 = 95 m

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