SSC CPO SI and ASI 2015 Paper

Question : 128 of 199

Marks: +1, -0

If A is an acute angle and cot A + cosec A = 3, then the value of sin A is

Solution:

(2)
We know that

\cosec ^{2} A-\cot ^{2} A=1,

(\cosece A-\cot A)

=\ {1}{(\csc A+\cot A)}=\frac{1}/{3}

Now,

2 \cosec A=3+\ {1}/{3}=\ {10}/{3}

\cosec A= {5}/{3}⇒ \sin A=\ {3}/{5}

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