SSC CPO SI and ASI 2015 Paper

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Question : 127 of 199

Marks: +1, -0

In the given figure, PAB is a secant and PT is a tangent to the circle from P. If PT = 5 cm, PA = 4 cm and AB = x cm, then x is

$4/9$ cm
$9/4$ cm
5 cm
$2/3$ cm

Solution:

(2)
since, PA

×{PB}=\ {PT}^{2}

Therefore,

4 \×(4+\ {x})=5^{2}

16+4 \ {x}=25

So,

x= {9}/{4} \ {cm}

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