SSC CPO SI and ASI 2014 Paper

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Question : 118 of 200

Marks: +1, -0

A train covers a distance of 10 km in 12 minutes. If its speed is decreased by 5 km/h, the time taken by it to cover the same distance is equal to

40 minutes
$40 /3$ minutes
20 minutes
15 minutes

Solution:

(2) Speed of train

= { { distance }}/{ { time }}= {10}/{ {12}/{60}}=50 {km} \/ {h}

New speed

=50-5=45 {km} \/ {h}

New time taken

= {10}/{45}= {2}/{9} h r= {2}/{9} × 60= {40}/{3} {min}

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