SSC CPO SI and ASI 2013 Paper

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Question : 137 of 200

Marks: +1, -0

In a triangle ABC, BC is produced to D so that CD = AC. If ∠BAD = 111° and ∠ACB = 80°, then the measure of ∠ABC is

31°
33°
35°
29°

Solution:

(4)

∠ ACD

=180°- 80° =100°

, and

∠{CAD}=∠{CDA}= {180-100}/{2}=40°

∠{BAC}=111°-40°=71°,

and
hence,

∠ A B C=180°-71°-80°=29°

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