SSC CPO SI and ASI 2013 Paper

Question : 129 of 200

Marks: +1, -0

Minimum value of 4 tan

^{2}

θ + 9 cot

^{2}

θ is

Solution:

(1) The value of

4 \tan ^{2} \θ+9 \cot ^{2} \θ

=(2 \tan \θ-3 \cot \θ)^{2}+12

since,

(2 \tan \θ-3 \cot \θ)^{2} ≥ 0,

therefore, minimum value = 12.

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