SSC CPO SI and ASI 2013 Paper

Question : 124 of 200

Marks: +1, -0

In the following figure, AB is the diameter of a circle whose centre is O. If ∠AOE = 150°, ∠DAO = 51°, then the measure of ∠CBE is

Solution:

(3) Given, ∠ DAO =51°
∠ AOE =150°
⇒∠ EOB =180°- 150°= 30°
OE = OB

∠ O E B=∠O B E=\ {150°}/{2}=75°

Now, ∠CBE =180°- 75°= 105°

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