SSC CPO SI and ASI 2012 Paper

Question : 121 of 200

Marks: +1, -0

A sector is formed by opening out a cone of base radius 8 cm and height 6 cm. Then the radius of the sector is (in cm)

Solution:

(3)Height (h) = 6 cm and base radius (r) = 8 cm,
then radius of sector will be the slant height of the cone.

1=\√{h^{2}+r^{2}}=\√{6^{2}+8^{2}}

=√{36+64}

=10 {cm}

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