SSC CPO SI and ASI 2011 Paper

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Question : 136 of 200

Marks: +1, -0

If the sum of

a/b

and its reciprocal is 1 and a ≠ 0, b ≠ 0, then the value of a

^{3}

+ b

^{3}

is

2
-1
0
1

Solution:

(3) Since,

{a}/{b}+ {b}/{a}=1

⇒ a^{2}+b^{2}=a b

⇒ a^{2}+b^{2}-a b=0

Therefore,

a^{3}+b^{3}=(a+b) (a^{2}+b^{2}-a b )=0

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