SSC CPO SI and ASI 2011 Paper

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Question : 104 of 200

Marks: +1, -0

If

\√{0.04 \× 0.4 × a}=0.004 \× 0.4 \× \√{b},

then thevalue of

a / b

is

16 × 10 $^{-3}$
16 × 10 $^{-4 }$
16 × 10 $^{-5 }$
16 × 10 $^{-6}$

Solution:

(3) On squaring both sides of

√{0.04 \× 0.4 \× a}=0.004 × 0.4 × √{b}

,
we get:

0.04 × 0.4 × a=

16 × 10^{-6} × 16 × 10^{-2} ×b,

therefore,

{a}/{b}= {16 × 16 × 10^{-8}}/{16 × 10^{-3}}=16 × 10^{-5}

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