SSC CPO SI and ASI 2011 Paper

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Question : 103 of 200

Marks: +1, -0

If (10.15)

^{2}

= 103.0225, then the value of

√{1030225}+\√{10302.25}

is

1025.15
103.515
102.515
102.0515

Solution:

(3) (10.15)

^{2}

= 103.0225,
it gives (101.5)

^{2}

= 10302.25 and (1.015)2 = 1.030225, so

√ {1.030225}+\√{10302.25}

=√{(1.015)^{2}}+\√{(101.5)^{2}}

=102.515

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