If x + y + z = 19, x 2 + y 2 + z 2 = 133 and xz = y 2 , x > z > 0, what is the value of (x - z) ?

SSC CPO 25 Nov 2020 Shift 1 Paper

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If x + y + z = 19, x² + y² + z² = 133 and xz = y², x > z > 0, what is the value of (x - z) ?

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