SSC CPO 25 Nov 2020 Shift 1 Paper

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Question : 126 of 200

Marks: +1, -0

If 4 - 2sin²θ - 5cosθ = 0, 0°< θ < 90°, then the value of cosθ - tanθ is:

$\;{1\;+\;2√3}/{2}$
$\;{2−√3}/{2}$
$\;{2\;+\;√3}/{2}$
$\;{1−2√3}/{2}$

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