SSC CHSL Model Paper 7

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Question : 42 of 100

Marks: +1, -0

If p = 999, then the value of

√^3{p(p^2 + 3p + 3) + 1}

is

1000
999
998
1002

Solution:

p = 999 (Given)
Expression ⇒

√^3{ p^3 + 3p ^2+ 3p + 1}

⇒

√^3{(p+1)^3 }

⇒

p+1 = 999+1 = 1000

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