If a^2= b+c,b^2=c+a,c^2=a+6, then the value of 1/{1+a}+ 1/{ b+1}+ 1/{ 1+c }

SSC CHSL Model Paper 7

Question : 40 of 100

Marks: +1, -0

a^2= b+c,b^2=c+a,c^2=a+6

, then the value of

1/{1+a}+ 1/{ b+1}+ 1/{ 1+c }

Solution:

1/{1+a}+ 1/{ b+1}+ 1/{ 1+c }

....(i)
Given that,

a^2 = b + c

a + a^2 = a + b + c

a(a+1) = a + b + c

(a+1)={a+ b + c}/a

1/{a+1}=a/{a+b+c}

Similarly,

1/{ b+1}=b/{a+b+c}

1/{ 1+c }=a/{a+b+c}

Put in eq. (i)
∴

a/{a+b+c} +b/{a+b+c}+c/{a+b+c}

={a+b+c}/{a+b+c}=1

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