SSC CHSL Model Paper 5

Question : 35 of 100

Marks: +1, -0

R and S start walking each other at 10 AM at the speeds of 3 km /h and 4 km /h respectively They were initially 17.5 km apart. At what time do they meet?

2 : 30 PM
11 : 30 AM
1 : 30 PM
12 : 30 PM

Validate

Solution:

Let after t hours they meet then,

3t + 4t = 17.5⇒t = 2.5

∴ Time = 10am + 2.5 h = 12:30 pm

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