SSC CHSL Model Paper 19

© examsiri.com

Question : 51 of 99

Marks: +1, -0

QUANTITATIVE APTITUDE

The value of

\sin^2 48° + \sin^2 42° - \sec^2 30°

+ \tan^2 60°

is equal to:

$8/3$
$2/3$
$7/3$
$5/3$

Solution:

\sin^2 48° + \sin^2 42° - \sec^2 30°

+ \tan^2 60°

=

\sin^2 48° + \sin^2 (90° - 48°)

- \sec^2 30° + \tan^2 60°

=

\sin^2 48° + \cos^2 48° - \sec^2 30° + \tan^2 60°

=1-(2/√3)^2+(√3)^2

=1-4/3+3

={3-4+9}/3=8/3

© examsiri.com

Go to Question:

Prev Question

Next Question