SSC CHSL Model Paper 13

Total number of students in college D, E and F = 48% of 1800 $=\frac{48\times 1800}{100}=864$
Number of girls in college D = 22% of 1800 $\times \frac{5}{11}$ = $\frac{22}{100}\times 1800\times \frac{5}{11}$ = 180
100 11Number of girls in college E = 10% of 1800 $\times \frac{3}{5}$ = $\frac{10}{100}\times 1800\times \frac{3}{5}$ = 108
Number of girls in college F = 16% of 1800 $\times \frac{7}{16}$ $=\frac{16}{100}\times 1800\times \frac{7}{16}=126$
Required percent $=\frac{180+108+126}{864}\times 100=47.9\%$