If \tan^2 A-\sin^2 A=x, then value of x is

SSC CHSL 9 Jan 2017 Shift 1 Paper

Question : 64 of 100

Marks: +1, -0

tan^2 A-sin^2 A=x

, then value of x is

Solution:

Expression :

tan^2 A-sin^2 A=x

{sin^2A}/{cos^2A}-sin^2A

sin^2A(1/{cos^2A}-1)

sin^2A({1 - cos^2A} /{cos^2A})

sin^2A({sin^2 A}/{cos^2A})

tan^2 Asin^2 A

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