SSC CHSL 8 Jan 2017 Shift 3 Paper

Question : 67 of 100

Marks: +1, -0

Chord AB of a circle when extended meets the tangent to the circle at point P. PT is the tangent touching the circle at point T. If lengths of PT and PB are 6 cm and 4 cm respectively, what is the length of PA?

12 cm
18 cm
27 cm
9 cm

Validate

Solution:

Given : PT = 6 cm and PB = 4 cm
To find : PA = ?
Solution : Using properties of tangents,

(PT)^2=PA×PB

⇒

(6)^2=(PA)×4

⇒

PA=36/4=9 cm

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