SSC CHSL 7 Mar 2018 Shift 2 Paper

Section: English Language

Question : 16 of 100

Marks: +1, -0

A truck moves at the speed of 90 km/hr after repairing and moves at the speed of 80 km/hr before repairing. It covers x distance in 8 hours after repairing. How much time (in hours) will it take to cover 4x distance before repairing?

Validate

Solution:

Speed of truck after repairing = 90 km/hr
Distance covered in 8 hours after repairing =

x

km
Using, speed = distance/time
⇒

90 =x/8

⇒

x=90×8=720

km
Speed of truck before repairing = 80 km/hr
Now, time taken (in hours) to cover km before repairing =

{4×720}/80 =36

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