SSC CHSL 7 Jan 2017 Shift 1 Paper

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Question : 69 of 100

Marks: +1, -0

If

4pxy = (x+2y)^2-(x-2y)^2

,then what will be the value of p?

0.5
0.25
4
2

Solution:

Expression :

4pxy = (x+2y)^2-(x-2y)^2

⇒

4pxy = (x^2+4y^2+4xy)

-(x^2+4y^2-4xy)

⇒

4pxy = (x^2-x^2)

+(4y^2-4y^2 )

+(4xy+4xy)

⇒

4pxy = 8xy

⇒ p =

8/4=2

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