SSC CHSL 15 Oct 2020 Shift 3 Paper

Question : 72 of 100

Marks: +1, -0

In the given figure

XYZ is a secant and ZT is a tangent. What is the value of

x

Solution:

Given,

By using secant properties, we get

\ZT^{2}=\ZX \.\ZY

⇒

(6)^{2}=(4+x) ×4=16+4 x

⇒

4 x=36-16=20

⇒

x={20}/{4}=5 {\cm}

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