SSC CHSL 15 Oct 2020 Shift 3 Paper

Question : 57 of 100

Marks: +1, -0

Find the value of

225-[42-\{25-(18-\ov {18+13})\}]

Solution:

Given expression,

=225-[42-\{25-(18-\ov {18+13})\}]

Solving on BODMAS, we get

225-[42-\{25-(18-18-13)\}]

=225-[42-\{25-(-13)\}]

=225-[42-\{25+13\}]

=225-[42-38]

=225-4=221

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