In the figure, '{\G}' is the centre of the circle. Find the \\angle \ACB when \\angle \AGB=150^\circ

SSC CHSL 15 Oct 2020 Shift 3 Paper

Question : 55 of 100

Marks: +1, -0

In the figure,

{\G}

' is the centre of the circle. Find the

\∠ \ACB

when

\∠ \AGB=150°

Solution:

We know that, the angle subtended by an arc of a circle at its centre is twice of the angle it subtends at any point on the circumference.
∴

\∠ \AGB=2 ×\∠ \ACB

⇒

2 ×\∠ \ACB=150°

∵ [given,

\∠\AGB=150°]

∴

\∠\ACB={150}/{2}=75°

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