SSC CHSL 15 Nov 2015 Shift 1 Paper

Question : 131 of 199

Marks: +1, -0

E is the midpoint if the median AD of

∆ABC

. BE is joined and produced to meet AC at F. F divides AC inthe ratio:

3 : 2
1 : 3
2 : 3
2 : 1

Validate

Solution:

Given : In ∆ABC, AD is the median and E is the mid point of AD.
Construction : Draw DP parallel to EF
To find = AF : FC
Solution : in ∆ADP, E is the mid point of AD and EF ∥ DP.
⇒ F is mid point of AP. [By converse of mid point theorem]
Similarly, in FBC, D is the mid point of BC and EF DP.
⇒ P is mid point of FC.
Thus, AF = FP = PC
∴

AF = 1/3{FC}

⇒ F divides AC in the ratio = 1 : 3

Go to Question:

Prev Question

Next Question