SSC CHSL 15 Nov 2015 Shift 1 Paper

Question : 130 of 199

Marks: +1, -0

The value of the following is:

(2 − 1/3 )(2 − 3/ 5 )(2 −5/ 7 )

.........(2 − 997/ 999 )

Solution:

Expression :

(2 − 1/3 )(2 − 3/ 5 )(2 −5/ 7 )

.........(2 − 997/ 999 )

( 5/3 )(7/5 )(9/7 )

............( 999 / 997 )( 1001/999 )

(Now, numerator of each term will get cancelled by the denominator of the next term, and we are left with)=

1001/3

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