If \tan \\theta=\frac{20}{21}, then the value of \frac{\sin \\theta-\cos \\theta}{\sin \\theta+\cos \\theta} is

SSC CHSL 12 Oct 2020 Shift 3 Paper

Question : 60 of 100

Marks: +1, -0

\tan \θ={20}/{21}

, then the value of

{\sin \θ-\cos \θ}/{\sin \θ+\cos \θ}

Solution:

{\sin \θ-\cos \θ}/{\sin \θ+\cos \θ}

On dividing numerator and denominator by

\cos \θ

, we get

={\tan \θ-1}/{\tan \θ+1}={{20}/{21}-1}/{{20}/{21}+1}

(\∵\tan \θ={20}/{21})

={({-1}/{21})}/{({41}/{21})}={-1}/{41}

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