SSC CHSL 12 Apr 2021 Shift 2 Paper

Section: Quantitative Aptitude

Question : 69 of 100

Marks: +1, -0

A shopkeeper sells two refrigerator sets at the same price. He gains

40 \%

on one refrigerator and losses

40 \%

on the other. What in his net loss percentage in the whole transaction?

Solution:

Given,

x=40 \%, y=-40 \%

Net per cent change in whole transaction

=(x+y+\;{x y}/{100}) \%

\;\; =(40-40-\;{40 × 40}/{100}) \%

=-16 \%

Where '-' sign shows the loss.

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