SSC CHSL 12 Apr 2021 Shift 2 Paper

Section: Quantitative Aptitude

Question : 65 of 100

Marks: +1, -0

What is the area (in

{m}^{2}

, up to 1 place of decimal) of an equilateral triangular field of side

8.5 {m}

Solution:

According to the question, Area of given equilateral triangular

\;\text " field "\;=\;{√{3}}/{4} ×(\;\text " side "\;)^{2}

\;\; =\;{√{3}}/{4} ×(8.5)^{2}=\;{√{3}}/{4} × 72.25

\;\; =18.0625 √{3} ≈ 18.1 √{3} {m}^{2}

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