SSC CHSL 10 Aug 2021 Shift 1 Paper

Section: Quantitative Aptitude

Question : 73 of 100

Marks: +1, -0

What is the sum of all the possible values of

k

for which a seven-digit number

23 k 567 k

is divisible by 3 ?

Solution:

For divisibility by 3 , sum of digits must be divisible by 3 ,

∴ 2+3+k+5+6+7+k=23+2 k

Since,

(23+2 k)

is divisible by 3

∴ \;23+2 k=27

⇒\;27-23=2 k

⇒\;2 k=4

⇒\;k=2

\; ∴ \;\text " Possible value of "\; k=2

\;\text " Next possible values of "\; k=5,8\;

∴ \;\;\text " Sum of all possible values of "\;

k=2+5+8=15

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