Let 0° < θ < 90° . (1 + cot 2 θ) (1 + tan 2 θ) × (sin θ – cosec θ )(cos θ – sec θ) is equal to:

Correct Answer is : sec θ cosec θ

SSC CGL Tier II Quant 29 Jan 2022 Paper

Question : 82 of 100

Marks: +1, -0

Let 0° < θ < 90° . (1 + cot² θ) (1 + tan² θ) × (sin θ – cosec θ )(cos θ – sec θ) is equal to:

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