( {\tan ^{3}\theta}/{ \sec ^{2}\theta} + {\cot ^{3}\theta}/{\cos ⁡ec^{2}\theta} + 2 \sin ⁡\theta\cos ⁡\theta)÷ (1 + cosec 2 θ + tan 2 θ), 0° < θ < 90° is equal to:

Correct Answer is : sin θ cos θ

SSC CGL Tier II Quant 29 Jan 2022 Paper

Question : 81 of 100

Marks: +1, -0

(\;{\tan\;^{3}θ}/{\ sec\;^{2}θ} + \;{\cot\;^{3}θ}/{\cos\;⁡ec^{2}θ} + 2 sin \;⁡θ\cos ⁡θ)

÷ (1 + cosec² θ + tan² θ), 0° < θ < 90° is equal to:

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