ABCD is a rectangle of which AC is a diagonal. The value of (\tan ^{2} \angle{CAD}+1 ) \sin ^{2} \angle{BAC} is

SSC CGL Tier II 21 Sep 2014 Paper

Question : 38 of 100

Marks: +1, -0

ABCD is a rectangle of which AC is a diagonal. The value of

(\tan ^{2} ∠{CAD}+1 ) \sin ^{2} ∠{BAC}

Solution:

(3)

∠ACD = 45°
∠BAC = 45°

∴ (\tan ^{2} ∠{CAD}+1 ) \sin ^{2} ∠{BAC}

= (\tan ^{2} 45°+1 ) \sin ^{2} 45°

=(1+1) ×( {1}/{√{2}} )^{2}=2 ×{1}/{2}=1

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