SSC CGL Tier II 12 Apr 2015 Paper

Question : 32 of 100

Marks: +1, -0

For an equilateral triangle, the ratio of the in-radius and the ex-radius is

Solution:

(1) In–radius

= { { Side }}/{2 √{3}}

Circum-radius

= { { Side }}/{\√{3}}

∴ Required ratio

= { { Side }}/{2 √{3}} : { { Side }}/{√{3}}

=√{3} : 2√{3}=1 : 2

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