SSC CGL Tier II 12 Apr 2015 Paper

Question : 15 of 100

Marks: +1, -0

The area of the parallelogram whose length is 30 cm, width is 20 cm and one diagonal is 40 cm is

Solution:

(4)

In Δ ABD, AB = 20 cm. AD = 30 cm.
BD = 40 cm.
∴ Semi–Perimeter (s)

= {a+b+c}/{2}= {20+30+40}/{2}

=45 {cm}

∴Area of ΔABD

=√{s(s-a)(s-b)(s-c)}

=√{45(45-20)(45-30)(45-40)}

=√{45 × 25× 15 × 5}

=√{5× 3 × 3 × 5 × 5× 5 × 3 × 5}

=√{5^{2} × 5^{2} × 5 × 3^{2} × 3}

=5 × 5 × 3 √{15}

=75√15

square cm.
∴ Area of parallelogram ABCD

=2× 75 √{15}

=150 √{15}

square cm.

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