SSC CGL Model Paper 5

Question : 75 of 100

Marks: +1, -0

ABC is an isosceles triangle in which AB = AC and ∠A = 2∠B. What is the ratio of inradius to the circum - radius?

Solution:

∠B = ∠C = 45° and ∠A = 90°
Inradius (r) =

{a + a - a √2}/2={a ( 2 -√2 )}/2

And circum -radius =

{a√2}/2

∴

\inradius/{\circum \radius }={{a ( 2 -√2 )}/2}/{{a√2}/2}

={2 -√2}/√2={√2-1}/1

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