What is the value of(1/\sqrt2) \cot 45^\circ+(1/\sqrt3) \cosec 60^\circ ?

SSC CGL Model Paper 20

Question : 69 of 100

Marks: +1, -0

What is the value of

(1/√2) \cot 45°+(1/√3) \cosec 60° ?

Solution:

(1/√2) \cot 45°+(1/√3) \cosec 60°

=1/√2×1+1/√3×2/√3

=1/√2+2/3=(3 + 2√2) / {3√2}

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