SSC CGL Model Paper 2

Question : 68 of 100

Marks: +1, -0

D and E are points on side AB and AC of ΔABC. DE is parallel to BC. If AD: DB = 2:5 and area of ΔADE is 8 sq cm what is the area (in sq cm) of quadrilateral BDEC ?

Validate

Solution:

∴ ΔADE ∼ ΔABC
⇒

{\Area \of \Δ\ADE}/{\Area \of \Δ\ABC}=(\AD/\AB)^2

⇒

8/{\Area \of \Δ\ABC}=(2/7)^2

⇒

8/{\Area \of \Δ\ABC}=4/49

⇒

{\Area \of \Δ\ABC}={49×8}/4

= 98 cm

^{2}

∴ Area of quadrilateral BDEC = Area of ΔABC - Area of ΔADE
= 98 - 8 = 90 cm

^{ 2}

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